version 1.1, 2000/03/01 02:25:51 |
version 1.2, 2000/03/28 01:59:21 |
Line 35 $ab \in I$ $B$+$D(B $a\notin I$ $B$J$i$P(B $b \in |
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Line 35 $ab \in I$ $B$+$D(B $a\notin I$ $B$J$i$P(B $b \in |
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$\sqrt{I} = \cap_{I\subset P:prime}P$ |
$\sqrt{I} = \cap_{I\subset P:prime}P$ |
\end{lm} |
\end{lm} |
\proof $I \subset P$ $B$J$i$P(B $\sqrt{I} \subset \sqrt{P}=P$ $B$h$j(B |
\proof $I \subset P$ $B$J$i$P(B $\sqrt{I} \subset \sqrt{P}=P$ $B$h$j(B |
$\subset$ $B$O(B OK. $B1&JU$,:8JU$r??$K4^$`$H$9$l$P(B, $B$"$k(B |
$B:8JU(B $\subset$ $B1&JU(B. $B1&JU$,:8JU$r??$K4^$`$H$9$l$P(B, $B$"$k(B |
$f \in \cap_{I\subset P:prime}P \setminus \sqrt{I}$ $B$,B8:_$9$k(B. $B$3$N$H$-(B, |
$f \in \cap_{I\subset P:prime}P \setminus \sqrt{I}$ $B$,B8:_$9$k(B. $B$3$N$H$-(B, |
$S=\{f,f^2,\cdots,\}$ $B$H$*$1$P(B, |
$S=\{f,f^2,\cdots,\}$ $B$H$*$1$P(B, |
$S \cap \sqrt{I} = \emptyset$. |
$S \cap \sqrt{I} = \emptyset$. |